[{"data":1,"prerenderedAt":2056},["ShallowReactive",2],{"subject-tin":3},[4,39,60,1599],{"id":5,"title":6,"body":7,"class":22,"description":19,"extension":23,"meta":24,"navigation":25,"path":27,"pdfDownload":28,"scope":29,"scopeName":30,"seo":31,"stem":32,"subject":33,"subjectName":34,"type":35,"typeName":36,"year":37,"__hash__":38},"faecher\u002Ffaecher\u002Ftin\u002F3-4-cs-sa2.md","Cheat-Sheet – Schulaufgabe 2",{"type":8,"value":9,"toc":18},"minimark",[10],[11,12,13],"p",{},[14,15],"img",{"alt":16,"src":17},"Seite 1","\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-cs-sa2_page_1.png",{"title":19,"searchDepth":20,"depth":20,"links":21},"",2,[],"3-4","md",{},{"title":26},"Cheat-Sheet – Schulaufgabe 2 (2023\u002F2024)","\u002Ffaecher\u002Ftin\u002F3-4-cs-sa2","\u002Fdownloads\u002FTIN\u002FTIN_3-4_CS_SA2.pdf","SA2","Schulaufgabe 2",{"title":6,"description":19},"faecher\u002Ftin\u002F3-4-cs-sa2","TIN","Technische Informatik","CS","Cheat-Sheet","2023\u002F2024","xjHrEqj6zHnrbV3XReViirp6zeFrWCmehn5-AZ_3qXE",{"id":40,"title":41,"body":42,"class":22,"description":19,"extension":23,"meta":51,"navigation":52,"path":54,"pdfDownload":55,"scope":29,"scopeName":30,"seo":56,"stem":57,"subject":33,"subjectName":34,"type":35,"typeName":58,"year":37,"__hash__":59},"faecher\u002Ffaecher\u002Ftin\u002F3-4-formelsammlung-sa2.md","Formelsammlung – Schulaufgabe 2",{"type":8,"value":43,"toc":49},[44],[11,45,46],{},[14,47],{"alt":16,"src":48},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-formelsammlung-sa2_page_1.png",{"title":19,"searchDepth":20,"depth":20,"links":50},[],{},{"title":53},"Formelsammlung – Schulaufgabe 2 (2023\u002F2024)","\u002Ffaecher\u002Ftin\u002F3-4-formelsammlung-sa2","\u002Fdownloads\u002FTIN\u002FFormelsammlung-SA2.pdf",{"title":41,"description":19},"faecher\u002Ftin\u002F3-4-formelsammlung-sa2","Formelsammlung","ZqGKSldClkXqsqkFAdnGEs77que9pRnCTHjqP5aRu1Y",{"id":61,"title":62,"body":63,"class":22,"description":1586,"extension":23,"meta":1587,"navigation":1588,"path":1590,"pdfDownload":1591,"scope":1592,"scopeName":1593,"seo":1594,"stem":1595,"subject":33,"subjectName":34,"type":1596,"typeName":1597,"year":37,"__hash__":1598},"faecher\u002Ffaecher\u002Ftin\u002F3-4-zsmf-sa1.md","Zusammenfassung – Schulaufgabe 1",{"type":8,"value":64,"toc":1540},[65,70,77,82,100,105,110,119,124,127,131,134,156,159,162,186,192,196,200,205,208,211,216,220,233,236,239,244,247,251,265,269,273,278,284,351,354,358,361,369,373,380,383,386,390,394,396,409,411,414,428,434,438,449,453,456,516,519,522,525,531,534,537,541,544,547,552,556,582,586,656,660,695,699,707,711,722,725,730,734,742,746,763,766,771,775,783,804,809,824,828,833,837,842,846,851,860,864,892,896,921,925,929,937,942,946,957,961,965,996,1000,1013,1016,1019,1022,1026,1037,1040,1043,1051,1072,1077,1081,1091,1095,1123,1127,1138,1141,1151,1155,1163,1166,1168,1174,1190,1195,1199,1203,1238,1243,1247,1262,1266,1280,1284,1289,1293,1332,1335,1349,1352,1366,1370,1373,1425,1428,1431,1465,1468,1498,1501,1504],[66,67,69],"h1",{"id":68},"zahlensysteme","Zahlensysteme",[11,71,72,76],{},[73,74,75],"strong",{},"Stellenwertsystem",": numerisches System, bei dem der Wert einer Ziffer durch ihre Position und die Basis des Systems bestimmt wird",[78,79,81],"h2",{"id":80},"binäres-zahlensystem","Binäres Zahlensystem",[83,84,85],"ul",{},[86,87,88,91,92],"li",{},[73,89,90],{},"Basis",": 2\n",[83,93,94,97],{},[86,95,96],{},"1 Bit: 2 Zustände (0 & 1)",[86,98,99],{},"8 Bit nennt man Oktett oder Byte",[101,102,104],"h3",{"id":103},"umrechnung","Umrechnung",[106,107,109],"h4",{"id":108},"binär-dezimal","Binär -> Dezimal",[111,112,113,116],"ol",{},[86,114,115],{},"Wert einer Stelle berechnen: Binärziffer * 2 Position der Binärziffer - 1",[86,117,118],{},"Werte addieren",[120,121,123],"h5",{"id":122},"beispiel","Beispiel",[11,125,126],{},"1101 -> (1 * 23) + (1 * 22) + (0 * 21) + (1 * 20) = 13",[106,128,130],{"id":129},"dezimal-binär","Dezimal -> Binär",[11,132,133],{},"Division mit ganzen Zahlen",[111,135,136,139,150,153],{},[86,137,138],{},"Division des Dezimalwertes durch 2",[86,140,141,142],{},"Rest aufschreiben\n",[111,143,144,147],{},[86,145,146],{},"Geht auf -> Rest: 0",[86,148,149],{},"Geht nicht auf -> Rest: 1",[86,151,152],{},"Wenn das Ergebnis nicht 0 ist, wieder bei 1. mit dem Ergebnis starten",[86,154,155],{},"Die Reste von unten nach oben ergeben die Binärzahl",[120,157,123],{"id":158},"beispiel-1",[11,160,161],{},"Dezimalzahl: 13",[111,163,164,170,176,181],{},[86,165,166,167],{},"13 \u002F 2 = 6 ",[73,168,169],{},"R: 1",[86,171,172,173],{},"6 \u002F 2 = 3 ",[73,174,175],{},"R: 0",[86,177,178,179],{},"3 \u002F 2 = 1 ",[73,180,169],{},[86,182,183,184],{},"1 \u002F 2 = 0 ",[73,185,169],{},[11,187,188,189],{},"13 -> ",[73,190,191],{},"1101",[101,193,195],{"id":194},"rechnungen","Rechnungen",[106,197,199],{"id":198},"addition","Addition",[83,201,202],{},[86,203,204],{},"Identisch zur schriftlichen Addition im Dezimalsystem",[120,206,123],{"id":207},"beispiel-2",[11,209,210],{},"1011 + 1110",[11,212,213],{},[14,214],{"alt":19,"src":215},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_1.png",[106,217,219],{"id":218},"multiplikation","Multiplikation",[83,221,222,225],{},[86,223,224],{},"Identisch zur schriftlichen Multiplikation im Dezimalsystem",[86,226,227,228],{},"Multiplikation ist komplexer als Addition\n",[83,229,230],{},[86,231,232],{},"Benötigt mehrere Taktzyklen",[120,234,123],{"id":235},"beispiel-3",[11,237,238],{},"101 * 11",[11,240,241],{},[14,242],{"alt":19,"src":243},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_2.png",[11,245,246],{},"101 * 11 = 1111",[120,248,250],{"id":249},"sonderfall-multiplikation-mit-2","Sonderfall: Multiplikation mit 2",[83,252,253,256,262],{},[86,254,255],{},"Bei einer Multiplikation mit 2 wird nur eine 0 angehängt",[86,257,258,259],{},"Fachbegriff für diese Aktion: ",[73,260,261],{},"Bitshift",[86,263,264],{},"Bitshift benötigt nur einen Taktzyklus",[106,266,268],{"id":267},"subtraktion","Subtraktion",[78,270,272],{"id":271},"hexadezimales-zahlensystem","Hexadezimales Zahlensystem",[11,274,275,277],{},[73,276,90],{},": 16",[11,279,280,283],{},[73,281,282],{},"Präfix",": 0x",[285,286,287,320],"table",{},[288,289,290],"thead",{},[291,292,293,299,302,305,308,311,314,317],"tr",{},[294,295,296],"th",{},[73,297,298],{},"Dezimal",[294,300,301],{},"0-9",[294,303,304],{},"10",[294,306,307],{},"11",[294,309,310],{},"12",[294,312,313],{},"13",[294,315,316],{},"14",[294,318,319],{},"15",[321,322,323],"tbody",{},[291,324,325,331,333,336,339,342,345,348],{},[326,327,328],"td",{},[73,329,330],{},"Hexadezimal",[326,332,301],{},[326,334,335],{},"A",[326,337,338],{},"B",[326,340,341],{},"C",[326,343,344],{},"D",[326,346,347],{},"E",[326,349,350],{},"F",[101,352,104],{"id":353},"umrechnung-1",[106,355,357],{"id":356},"hexadezimal-binär","Hexadezimal -> Binär",[11,359,360],{},"1 Hexadezimalziffer = 4 Binärstellen",[111,362,363,366],{},[86,364,365],{},"Hexadezimalziffern in je 4 Binärstellen umrechnen",[86,367,368],{},"Binärstellen aneinanderhängen",[106,370,372],{"id":371},"hexadezimal-dezimal","Hexadezimal -> Dezimal",[111,374,375,378],{},[86,376,377],{},"Wert einer Stelle berechnen: Dezimale Wertigkeit der Hexadezimalziffer * 16 Position der Binärziffer - 1",[86,379,118],{},[120,381,123],{"id":382},"beispiel-4",[11,384,385],{},"0xAFFE -> (10 * 163) + (15 * 162) + (15 * 161) + (14 * 160) = 45054",[106,387,389],{"id":388},"dezimal-hexadezimal","Dezimal -> Hexadezimal",[120,391,393],{"id":392},"möglichkeit-1-division-tr","Möglichkeit 1: Division (TR)",[11,395,133],{},[111,397,398,401,404,406],{},[86,399,400],{},"Division des Dezimalwertes durch 16",[86,402,403],{},"Rest aufschreiben",[86,405,152],{},[86,407,408],{},"Die Reste von unten nach oben ergeben die Hexadezimalzahl",[11,410,123],{},[11,412,413],{},"Dezimalzahl: 254",[111,415,416,422],{},[86,417,418,419],{},"254 \u002F 16 = 15 ",[73,420,421],{},"R: 14 -> E",[86,423,424,425],{},"15 \u002F 16 = 0 ",[73,426,427],{},"R: 15 -> F",[11,429,430,431],{},"254 -> ",[73,432,433],{},"0xFE",[120,435,437],{"id":436},"möglichkeit-2-über-binärsystem","Möglichkeit 2: Über Binärsystem",[83,439,440,443,446],{},[86,441,442],{},"Division durch 2 ist einfacher als durch 16",[86,444,445],{},"Binärergebnis in 4er Blöcke unterteilen",[86,447,448],{},"4er Blöcke in Hexadezimalzahl umrechnen",[450,451,123],"h6",{"id":452},"beispiel-5",[11,454,455],{},"Dezimalzahl: 3925",[111,457,458,463,468,473,478,483,488,493,498,503,508,512],{},[86,459,460,461],{},"3925 \u002F 2 = 1962 ",[73,462,169],{},[86,464,465,466],{},"1962 \u002F 2 = 981 ",[73,467,175],{},[86,469,470,471],{},"981 \u002F 2 = 490 ",[73,472,169],{},[86,474,475,476],{},"490 \u002F 2 = 245 ",[73,477,175],{},[86,479,480,481],{},"245 \u002F 2 = 122 ",[73,482,169],{},[86,484,485,486],{},"122 \u002F 2 = 61 ",[73,487,175],{},[86,489,490,491],{},"61 \u002F 2 = 30 ",[73,492,169],{},[86,494,495,496],{},"30 \u002F 2 = 15 ",[73,497,175],{},[86,499,500,501],{},"15 \u002F 2 = 7 ",[73,502,169],{},[86,504,505,506],{},"7 \u002F 2 = 3 ",[73,507,169],{},[86,509,178,510],{},[73,511,169],{},[86,513,183,514],{},[73,515,169],{},[11,517,518],{},"3925 -> 111101010101",[11,520,521],{},"1111 – 0101 – 0101",[11,523,524],{},"F 5 5",[11,526,527,528],{},"3925 -> ",[73,529,530],{},"0xF55",[101,532,195],{"id":533},"rechnungen-1",[106,535,199],{"id":536},"addition-1",[83,538,539],{},[86,540,204],{},[120,542,123],{"id":543},"beispiel-6",[11,545,546],{},"0xAFFE + 0x1111",[11,548,549],{},[14,550],{"alt":19,"src":551},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_3.png",[66,553,555],{"id":554},"binäre-logik","Binäre Logik",[83,557,558,564,570,576],{},[86,559,560,563],{},[73,561,562],{},"Binäre Variablen",": Nur zwei Zustände (0 & 1)",[86,565,566,569],{},[73,567,568],{},"Logiktabelle",": Enthält alle möglichen Kombinationen der Eingänge inklusive der entsprechenden Ausgänge",[86,571,572,575],{},[73,573,574],{},"Schaltfunktion",": Mathematischer Zusammenhang zwischen Eingang und Ausgang",[86,577,578,581],{},[73,579,580],{},"Logikblock",": Darstellung der logischen Verknüpfung der Variablen",[78,583,585],{"id":584},"grundfunktionen","Grundfunktionen",[285,587,588,610],{},[288,589,590],{},[291,591,592,597,601,606],{},[294,593,594],{},[73,595,596],{},"Name",[294,598,599],{},[73,600,568],{},[294,602,603],{},[73,604,605],{},"Funktion",[294,607,608],{},[73,609,580],{},[321,611,612,623,634,645],{},[291,613,614,617,619,621],{},[326,615,616],{},"Gleich",[326,618],{},[326,620],{},[326,622],{},[291,624,625,628,630,632],{},[326,626,627],{},"Nicht",[326,629],{},[326,631],{},[326,633],{},[291,635,636,639,641,643],{},[326,637,638],{},"Und",[326,640],{},[326,642],{},[326,644],{},[291,646,647,650,652,654],{},[326,648,649],{},"Oder",[326,651],{},[326,653],{},[326,655],{},[78,657,659],{"id":658},"abgeleitete-verknüpfungen","Abgeleitete Verknüpfungen",[285,661,662,682],{},[288,663,664],{},[291,665,666,670,674,678],{},[294,667,668],{},[73,669,596],{},[294,671,672],{},[73,673,568],{},[294,675,676],{},[73,677,605],{},[294,679,680],{},[73,681,580],{},[321,683,684],{},[291,685,686,689,691,693],{},[326,687,688],{},"Exklusives  Oder",[326,690],{},[326,692],{},[326,694],{},[78,696,698],{"id":697},"disjunktive-normalform-oder-normalform","Disjunktive Normalform (ODER-Normalform)",[83,700,701,704],{},[86,702,703],{},"Spezielle Form einer logischen Formel",[86,705,706],{},"Besteht aus beliebig vielen Konjunktionen (UND) verknüpft durch Disjunktionen (ODER)",[101,708,710],{"id":709},"bildung-einer-dnf-aus-einer-wertetabelle","Bildung einer DNF aus einer Wertetabelle",[111,712,713,716,719],{},[86,714,715],{},"Alle wahren Zeilen finden",[86,717,718],{},"Konjunktion für jede wahre Zeile erstellen",[86,720,721],{},"Jede erstellte Konjunktion mit einem ODER verknüpfen",[101,723,123],{"id":724},"beispiel-7",[83,726,727],{},[86,728,729],{},"Drei Konjunktionen verbunden durch zwei ODER-Verknüpfungen",[78,731,733],{"id":732},"kv-diagramm","KV-Diagramm",[83,735,736,739],{},[86,737,738],{},"Diagramm um die minimalste Formel einer Schaltung zu ermitteln",[86,740,741],{},"Anzahl der Zellen: 2 Anzahl der Eingangsvariablen",[101,743,745],{"id":744},"minimalisierung-mit-einem-kv-diagramm-aus-einer-wertetabelle","Minimalisierung mit einem KV-Diagramm aus einer Wertetabelle",[111,747,748,751,754,757,760],{},[86,749,750],{},"Übertragen der 1-Zustände in das KV-Diagramm",[86,752,753],{},"Rest mit 0-Zuständen auffüllen",[86,755,756],{},"Alle benachbarten Zellen umranden (auch über die Kanten des Diagramms hinaus auf die andere Seite)",[86,758,759],{},"Einzelne Blöcke bestehen nur noch aus Variablen, die sich innerhalb des Blockes nicht verändern",[86,761,762],{},"Blöcke mit ODER-Verknüpfungen miteinander verbinden",[106,764,123],{"id":765},"beispiel-8",[11,767,768],{},[14,769],{"alt":19,"src":770},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_9.png",[66,772,774],{"id":773},"volladdierer","Volladdierer",[83,776,777,780],{},[86,778,779],{},"Addieren mit binären Operationen",[86,781,782],{},"3 Eingänge notwendig",[111,784,785,792,798],{},[86,786,787,788,791],{},"Erster Summand (",[73,789,790],{},"x",")",[86,793,794,795,791],{},"Zweiter Summand (",[73,796,797],{},"y",[86,799,800,801,791],{},"Carry – In: Übertrag von vorherigem Durchgang (",[73,802,803],{},"Cin",[83,805,806],{},[86,807,808],{},"2 Ausgänge",[111,810,811,817],{},[86,812,813,814,791],{},"Summe aus erstem und zweitem Summanden (",[73,815,816],{},"s",[86,818,819,820,823],{},"Carry – Out: Übertrag aus der Summe (",[73,821,822],{},"Cout",") -> wird Carry – In",[78,825,827],{"id":826},"schaltung-eines-volladierers","Schaltung eines Volladierers",[11,829,830],{},[14,831],{"alt":19,"src":832},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_10.png",[78,834,836],{"id":835},"wahrheitstabelle-eines-volladdierers","Wahrheitstabelle eines Volladdierers",[11,838,839],{},[14,840],{"alt":19,"src":841},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_11.png",[78,843,845],{"id":844},"schaltung-eines-halbaddierers","Schaltung eines Halbaddierers",[11,847,848],{},[14,849],{"alt":19,"src":850},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_12.png",[11,852,853,854],{},"Quelle: ",[855,856,857],"a",{"href":857,"rel":858},"https:\u002F\u002Fwww.youtube.com\u002Fwatch?v=Od-9-vIJapo",[859],"nofollow",[66,861,863],{"id":862},"multiplexer","Multiplexer",[83,865,866,869,872,875],{},[86,867,868],{},"Digitale Schaltung",[86,870,871],{},"Mehrere Eingangssignale auf einen Ausgang",[86,873,874],{},"Über Steuerleitungen wird entschieden welcher Eingang gewählt wird",[86,876,877,878],{},"Typen:\n",[83,879,880,886],{},[86,881,882,885],{},[73,883,884],{},"N-zu-1 Multiplexer",": Wählt eines von N Eingangssignalen aus",[86,887,888,891],{},[73,889,890],{},"1-zu-N Demultiplexer",": Verteilt einen Ausgang auf einen von N Ausgängen",[78,893,895],{"id":894},"anwendungen","Anwendungen",[83,897,898,909,915],{},[86,899,900,903,904],{},[73,901,902],{},"Datenübertragung",": Telekommunikation verwendet Multiplexer, um mehrere Datenströme über eine Leitung zu übertragen\n",[83,905,906],{},[86,907,908],{},"Erhöht Effizienz",[86,910,911,914],{},[73,912,913],{},"Schaltnetzwerke",": Multiplexer ermöglichen das Routing in Schaltnetzwerken",[86,916,917,920],{},[73,918,919],{},"Adressierung in Speichern",": Zur Auswahl des richtigen Speicherorts in Speicheradressierungssystemen",[78,922,924],{"id":923},"beispiele","Beispiele",[101,926,928],{"id":927},"_1-mux","1-Mux",[11,930,931,934],{},[14,932],{"alt":19,"src":933},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_13.png",[14,935],{"alt":19,"src":936},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_14.png",[11,938,939],{},[14,940],{"alt":19,"src":941},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_15.png",[101,943,945],{"id":944},"_2-mux","2-Mux",[11,947,948,951,954],{},[14,949],{"alt":19,"src":950},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_16.png",[14,952],{"alt":19,"src":953},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_17.png",[14,955],{"alt":19,"src":956},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_18.png",[66,958,960],{"id":959},"darstellung-negativer-zahlen","Darstellung negativer Zahlen",[78,962,964],{"id":963},"einerkomplement","Einerkomplement",[83,966,967,970,979,990,993],{},[86,968,969],{},"Veralteter Standard",[86,971,972,975,976],{},[73,973,974],{},"MSB",": Most Significant Bit -> ",[73,977,978],{},"Das linkeste Bit",[86,980,981,982],{},"MSB wird verwendet um das Vorzeichen zu wählen\n",[83,983,984,987],{},[86,985,986],{},"0: Positiv",[86,988,989],{},"1: Negativ",[86,991,992],{},"Größte Positive Zahl: 2Anzahl Bits – 1 – 1",[86,994,995],{},"Größte Negative Zahl: -2Anzahl Bits – 1 – 1",[101,997,999],{"id":998},"bildung-des-einerkomplements","Bildung des Einerkomplements",[83,1001,1002],{},[86,1003,1004,1005],{},"Alle Bits einer Binärzahl invertieren\n",[83,1006,1007,1010],{},[86,1008,1009],{},"Aus 0 wird 1",[86,1011,1012],{},"Aus 1 wird 0",[106,1014,123],{"id":1015},"beispiel-9",[11,1017,1018],{},"Binärzahl: 010110",[11,1020,1021],{},"Einerkomplement der Binärzahl: 101001",[101,1023,1025],{"id":1024},"subtraktion-mit-dem-einerkomplement","Subtraktion mit dem Einerkomplement",[111,1027,1028,1031,1034],{},[86,1029,1030],{},"Subtrahend invertieren um das Vorzeichen zu setzen",[86,1032,1033],{},"Minuend und invertierten Subtrahend addieren",[86,1035,1036],{},"Bei einem Überlauf, den Überlauf zum Ergebnis addieren",[106,1038,123],{"id":1039},"beispiel-10",[11,1041,1042],{},"4-3",[83,1044,1045,1048],{},[86,1046,1047],{},"4: 0100",[86,1049,1050],{},"3: 0011",[111,1052,1053,1061,1064],{},[86,1054,1055,1056],{},"Subtrahend Invertieren\n",[111,1057,1058],{},[86,1059,1060],{},"0011 -> 1100",[86,1062,1063],{},"0100 + 1100 = 1 0000",[86,1065,1066,1067],{},"Überlauf addieren\n",[111,1068,1069],{},[86,1070,1071],{},"0000 + 0001 = 0001",[83,1073,1074],{},[86,1075,1076],{},"Ergebnis: 1",[106,1078,1080],{"id":1079},"problem","Problem",[83,1082,1083],{},[86,1084,1085,1086],{},"Wenn es einen Übertritt über 0 gibt\n",[83,1087,1088],{},[86,1089,1090],{},"Z.B. 6-4",[78,1092,1094],{"id":1093},"zweierkomplement","Zweierkomplement",[83,1096,1097,1100,1103,1110,1118,1120],{},[86,1098,1099],{},"Einheitliche Darstellung",[86,1101,1102],{},"Löst einige Probleme des Einerkomplements",[86,1104,1105,975,1107],{},[73,1106,974],{},[73,1108,1109],{},"das linkeste Bit",[86,1111,981,1112],{},[83,1113,1114,1116],{},[86,1115,986],{},[86,1117,989],{},[86,1119,992],{},[86,1121,1122],{},"Größte Negative Zahl: -2Anzahl Bits – 1",[101,1124,1126],{"id":1125},"bildung-des-zweierkomplements","Bildung des Zweierkomplements",[111,1128,1129,1132,1135],{},[86,1130,1131],{},"Binärzahl ermitteln",[86,1133,1134],{},"Einerkomplement bilden",[86,1136,1137],{},"1 zum Einerkomplement addieren",[106,1139,123],{"id":1140},"beispiel-11",[111,1142,1143,1145,1148],{},[86,1144,1018],{},[86,1146,1147],{},"Einerkomplement: 010110 -> 101001",[86,1149,1150],{},"1 Addieren: 101001 + 1 = 101010",[101,1152,1154],{"id":1153},"subtraktion-mit-dem-zweierkomplement","Subtraktion mit dem Zweierkomplement",[111,1156,1157,1160],{},[86,1158,1159],{},"Zweierkomplement vom Subtrahend bilden",[86,1161,1162],{},"Minuend und Subtrahend addieren",[106,1164,123],{"id":1165},"beispiel-12",[11,1167,1042],{},[83,1169,1170,1172],{},[86,1171,1047],{},[86,1173,1050],{},[111,1175,1176,1187],{},[86,1177,1178,1179],{},"Zweierkomplement bilden\n",[111,1180,1181,1184],{},[86,1182,1183],{},"Einerkomplement bilden: 0011 -> 1100",[86,1185,1186],{},"1 Addieren: 1100 + 1 = 1101",[86,1188,1189],{},"Addieren: 0100 + 1101 = 1 0001",[83,1191,1192],{},[86,1193,1194],{},"Übertrag entfällt, da nur 4 Bit",[66,1196,1198],{"id":1197},"rationale-zahlen","Rationale Zahlen",[78,1200,1202],{"id":1201},"festkommaarithmetik","Festkommaarithmetik",[83,1204,1205,1221,1224,1227],{},[86,1206,1207,1208],{},"Position des Kommas ist vorgegeben\n",[83,1209,1210],{},[86,1211,1212,1213],{},"Beispiel (8Bit)\n",[83,1214,1215,1218],{},[86,1216,1217],{},"4-Bits vor dem Komma",[86,1219,1220],{},"4-Bits nach dem Komma",[86,1222,1223],{},"Begrenzte Genauigkeit durch feste Kommaposition",[86,1225,1226],{},"Grundrechenarten sind ähnlich wie bei Dezimalzahlen",[86,1228,1229,1230],{},"Anwendung in:\n",[83,1231,1232,1235],{},[86,1233,1234],{},"Eingebetteten Systemen",[86,1236,1237],{},"Anwendungen bei denen eine feste Anzahl von Bits vor\u002Fnach dem Komma erforderlich ist (Bildverarbeitung)",[11,1239,1240],{},[14,1241],{"alt":19,"src":1242},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_19.png",[101,1244,1246],{"id":1245},"vorteile","Vorteile",[83,1248,1249],{},[86,1250,1251,1254],{},[73,1252,1253],{},"Einfachheit",[83,1255,1256,1259],{},[86,1257,1258],{},"Erfordert weniger komplexe Hardware",[86,1260,1261],{},"Kann effizienter implementieret werden+",[101,1263,1265],{"id":1264},"nachteile","Nachteile",[83,1267,1268,1274],{},[86,1269,1270,1273],{},[73,1271,1272],{},"Begrenzte Dynamik",": Sehr große oder sehr kleine Werte werden ggf. ungenau",[86,1275,1276,1279],{},[73,1277,1278],{},"Genauigkeitsverlust",": Berechnung mit komplexen Zahlen kann zu Rundungsfehlern führen",[101,1281,1283],{"id":1282},"beispiel-für-addition","Beispiel für Addition",[11,1285,1286],{},[14,1287],{"alt":19,"src":1288},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_20.png",[78,1290,1292],{"id":1291},"fließkommaarithmetik","Fließkommaarithmetik",[83,1294,1295,1298,1318,1326,1329],{},[86,1296,1297],{},"Komma kann verschoben werden",[86,1299,1300,1301],{},"Bestandteile:\n",[83,1302,1303,1308,1313],{},[86,1304,1305],{},[73,1306,1307],{},"1 Bit: Vorzeichen",[86,1309,1310],{},[73,1311,1312],{},"8 Bit: Exponent",[86,1314,1315],{},[73,1316,1317],{},"23 Bit: Mantisse",[86,1319,1320,1321],{},"Innerhalb der Mantisse lässt sich das Komma verschieben\n",[83,1322,1323],{},[86,1324,1325],{},"Große und kleine Zahlen mit unterschiedlicher Genauigkeit",[86,1327,1328],{},"Hohe Dynamik und Genauigkeit",[86,1330,1331],{},"Erfordert spezielle Algorithmen um den Exponenten und die Mantisse festzulegen",[101,1333,1246],{"id":1334},"vorteile-1",[83,1336,1337,1343],{},[86,1338,1339,1342],{},[73,1340,1341],{},"Hohe Genauigkeit und Dynamik",": Breiter Bereich von Zahlen mit unterschiedlicher Genauigkeit",[86,1344,1345,1348],{},[73,1346,1347],{},"Flexibilität",": Durch das Verschieben des Kommas",[101,1350,1265],{"id":1351},"nachteile-1",[83,1353,1354,1360],{},[86,1355,1356,1359],{},[73,1357,1358],{},"Komplexität",": Erfordert komplexe Algorithmen und Hardware",[86,1361,1362,1365],{},[73,1363,1364],{},"Rundungsfehler",": Bei komplexen Berechnungen oder Darstellung von Zahlen die nicht in das Gleitkommazahlenformat passen",[101,1367,1369],{"id":1368},"berechnung-einer-gleitkommazahl","Berechnung einer Gleitkommazahl",[106,1371,130],{"id":1372},"dezimal-binär-1",[111,1374,1375,1386,1389,1392,1395,1406,1417],{},[86,1376,1377,1378],{},"Vorzeichenbit festlegen\n",[111,1379,1380,1383],{},[86,1381,1382],{},"Positiv: 0",[86,1384,1385],{},"Negativ: 1",[86,1387,1388],{},"Vorkommazahl umrechnen",[86,1390,1391],{},"Nachkommazahl umrechnen",[86,1393,1394],{},"Gesamtzahl bilden durch Verkettung von Vor- & Nachkommazahl",[86,1396,1397,1398],{},"Normieren: Es darf & muss nur eine 1 vor dem Komma stehen\n",[111,1399,1400,1403],{},[86,1401,1402],{},"Verschiebung durch 2 Stellen um die Verschoben wird",[86,1404,1405],{},"Alles nach dem Komma ist die Mantisse",[86,1407,1408,1409],{},"Exponent umrechnen: Verschobene Stellen + 127 = Exponent\n",[111,1410,1411,1414],{},[86,1412,1413],{},"Verschobene Stellen können ggf. auch negativ sein",[86,1415,1416],{},"In Binär umrechnen",[86,1418,1419,1420],{},"Vorzeichen, Exponent und Mantisse in dieser Reihenfolge verketten\n",[111,1421,1422],{},[86,1423,1424],{},"Rest mit 0en auffüllen",[120,1426,123],{"id":1427},"beispiel-13",[11,1429,1430],{},"Ausgangszahl: 18,4",[111,1432,1433,1436,1439,1445,1448,1459,1462],{},[86,1434,1435],{},"Vorzeichen: Positiv -> 0",[86,1437,1438],{},"Vorkommazahl: 18 -> 10010",[86,1440,1441,1444],{},[14,1442],{"alt":19,"src":1443},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa1_img_21.png","Nachkommazahl umrechnen: 0,4 -> 0110",[86,1446,1447],{},"Gesamtzahl bilden: 10010,0110",[86,1449,1450,1451],{},"Normieren: Komma muss um 4 Stellen verschoben werden\n",[111,1452,1453,1456],{},[86,1454,1455],{},"10010,0110 = 1,00100110 * 24",[86,1457,1458],{},"Mantisse: 00100110",[86,1460,1461],{},"Exponent bestimmen: 4 + 127 = 131 -> 10000011",[86,1463,1464],{},"Verketten und 0en auffüllen: 0 10000011 00100110 000000000000000",[106,1466,109],{"id":1467},"binär-dezimal-1",[111,1469,1470,1473,1476,1484,1492,1495],{},[86,1471,1472],{},"Einteilung in Vorzeichenbit, Exponent und Mantisse",[86,1474,1475],{},"Vorzeichen merken",[86,1477,1478,1479],{},"Exponentenbereich in Dezimal umrechnen\n",[111,1480,1481],{},[86,1482,1483],{},"Dezimalzahl – 127 = Exponent",[86,1485,1486,1487],{},"Komma der Mantisse entsprechend verschieben\n",[111,1488,1489],{},[86,1490,1491],{},"Führende 1 vor dem Komma behalten!",[86,1493,1494],{},"Vor- & Nachkommazahl in Dezimalumrechnen und verketten",[86,1496,1497],{},"Vorzeichen setzen",[120,1499,123],{"id":1500},"beispiel-14",[11,1502,1503],{},"Ausgangszahl: 10111111000000000000000000000000",[111,1505,1506,1509,1512,1520,1523,1534,1537],{},[86,1507,1508],{},"Einteilen: 1-01111110-00000000000000000000000",[86,1510,1511],{},"Vorzeichen: 1 -> -",[86,1513,1514,1515],{},"Exponent in Dezimal: 126\n",[111,1516,1517],{},[86,1518,1519],{},"126 – 127 = -1",[86,1521,1522],{},"Komma der Mantisse verschieben: 1,0 -> 0,1",[86,1524,1525,1526],{},"In Dezimal umrechnen\n",[111,1527,1528,1531],{},[86,1529,1530],{},"Vorkomma: 0 -> 0",[86,1532,1533],{},"Nachkomma: 1 -> ,5",[86,1535,1536],{},"Verketten: 0,5",[86,1538,1539],{},"Vorzeichen setzen: -0,5",{"title":19,"searchDepth":20,"depth":20,"links":1541},[1542,1547,1551,1552,1553,1557,1560,1561,1562,1563,1564,1568,1572,1576,1581],{"id":80,"depth":20,"text":81,"children":1543},[1544,1546],{"id":103,"depth":1545,"text":104},3,{"id":194,"depth":1545,"text":195},{"id":271,"depth":20,"text":272,"children":1548},[1549,1550],{"id":353,"depth":1545,"text":104},{"id":533,"depth":1545,"text":195},{"id":584,"depth":20,"text":585},{"id":658,"depth":20,"text":659},{"id":697,"depth":20,"text":698,"children":1554},[1555,1556],{"id":709,"depth":1545,"text":710},{"id":724,"depth":1545,"text":123},{"id":732,"depth":20,"text":733,"children":1558},[1559],{"id":744,"depth":1545,"text":745},{"id":826,"depth":20,"text":827},{"id":835,"depth":20,"text":836},{"id":844,"depth":20,"text":845},{"id":894,"depth":20,"text":895},{"id":923,"depth":20,"text":924,"children":1565},[1566,1567],{"id":927,"depth":1545,"text":928},{"id":944,"depth":1545,"text":945},{"id":963,"depth":20,"text":964,"children":1569},[1570,1571],{"id":998,"depth":1545,"text":999},{"id":1024,"depth":1545,"text":1025},{"id":1093,"depth":20,"text":1094,"children":1573},[1574,1575],{"id":1125,"depth":1545,"text":1126},{"id":1153,"depth":1545,"text":1154},{"id":1201,"depth":20,"text":1202,"children":1577},[1578,1579,1580],{"id":1245,"depth":1545,"text":1246},{"id":1264,"depth":1545,"text":1265},{"id":1282,"depth":1545,"text":1283},{"id":1291,"depth":20,"text":1292,"children":1582},[1583,1584,1585],{"id":1334,"depth":1545,"text":1246},{"id":1351,"depth":1545,"text":1265},{"id":1368,"depth":1545,"text":1369},"Stellenwertsystem: numerisches System, bei dem der Wert einer Ziffer durch ihre Position und die Basis des Systems bestimmt wird",{},{"title":1589},"Zusammenfassung – Schulaufgabe 1 (2023\u002F2024)","\u002Ffaecher\u002Ftin\u002F3-4-zsmf-sa1","\u002Fdownloads\u002FTIN\u002FTIN_3-4_ZSMF_SA1.pdf","SA1","Schulaufgabe 1",{"title":62,"description":1586},"faecher\u002Ftin\u002F3-4-zsmf-sa1","ZSMF","Zusammenfassung","Z2eLyPNi-vwaWUfWISLg98fWPyBkd8gCHS_QWqQE4Ag",{"id":1600,"title":1601,"body":1602,"class":22,"description":19,"extension":23,"meta":2048,"navigation":2049,"path":2051,"pdfDownload":2052,"scope":29,"scopeName":30,"seo":2053,"stem":2054,"subject":33,"subjectName":34,"type":1596,"typeName":1597,"year":37,"__hash__":2055},"faecher\u002Ffaecher\u002Ftin\u002F3-4-zsmf-sa2.md","Zusammenfassung – Schulaufgabe 2",{"type":8,"value":1603,"toc":2026},[1604,1608,1619,1623,1627,1630,1634,1645,1649,1702,1706,1710,1729,1733,1749,1753,1756,1761,1765,1770,1774,1779,1783,1788,1792,1796,1800,1803,1811,1814,1822,1825,1828,1831,1834,1839,1843,1847,1850,1858,1863,1867,1870,1889,1894,1898,1922,1927,1931,1950,1955,1959,1978,1983,1988,1992,1996,2009,2013],[66,1605,1607],{"id":1606},"energiespeicher-kondensator","Energiespeicher: Kondensator",[83,1609,1610,1613,1616],{},[86,1611,1612],{},"Zwei Gegenüberliegende Metallplatten; Dazwischen Luft",[86,1614,1615],{},"Durch anliegende Spannung werden Ladungsteilchen der Luft an entsprechende Metallplatten gedrückt; Nach kurzer Zeit fließt kein Strom mehr.",[86,1617,1618],{},"Speichert Energie verlustfrei ABER beim laden\u002Fentladen entsteht Verlustleistung über den Ladewiderstand.",[78,1620,1622],{"id":1621},"kapazität-gemessen-in-farad","Kapazität (Gemessen in ‚Farad‘):",[66,1624,1626],{"id":1625},"feldeffekttransistor-mosfet","Feldeffekttransistor (MOSFET)",[11,1628,1629],{},"Anwendung in CMOS Logikschaltungen",[78,1631,1633],{"id":1632},"anschlüsse","Anschlüsse",[83,1635,1636,1639,1642],{},[86,1637,1638],{},"Drain: Stromabfluss \u002F Ground",[86,1640,1641],{},"Gate: Steueranschluss des Schalters",[86,1643,1644],{},"Source: Stromquelle \u002F Pluspol",[78,1646,1648],{"id":1647},"bauform","Bauform",[83,1650,1651,1681],{},[86,1652,1653,1656,1657],{},[14,1654],{"alt":19,"src":1655},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_1.png","P oder N Kanal:\n",[83,1658,1659,1670],{},[86,1660,1661,1662],{},"P-Kanal: Pfeil in Positive Richtung\n",[83,1663,1664,1667],{},[86,1665,1666],{},"Strom fließt von Source zu Drain",[86,1668,1669],{},"Reagiert auf negative Spannung zwischen Source & Gate",[86,1671,1672,1673],{},"N-Kanal: Pfeil in negative Richtung\n",[83,1674,1675,1678],{},[86,1676,1677],{},"Strom fließt von Drain zu Source",[86,1679,1680],{},"Reagiert auf positive Spannung zwischen Source & Gate",[86,1682,1683,1684],{},"‚Normal leitend‘ oder ‚Normal sperrend‘\n",[83,1685,1686,1694],{},[86,1687,1688,1689],{},"Leitend: Durchgezogene Linie\n",[83,1690,1691],{},[86,1692,1693],{},"Ohne Gatespannung Stromfluss",[86,1695,1696,1697],{},"Sperrend: Unterbrochene \u002F Gestrichelte Linie\n",[83,1698,1699],{},[86,1700,1701],{},"Ohne Gatespannung kein Stromfluss",[66,1703,1705],{"id":1704},"sram-dram-flüchtige-speicher","SRAM & DRAM (Flüchtige Speicher)",[78,1707,1709],{"id":1708},"sram-static-random-access-memory","SRAM: Static Random Access Memory",[83,1711,1712,1720,1723,1726],{},[86,1713,1714,1715],{},"Schneller Speicher – Kleine Kapazität\n",[83,1716,1717],{},[86,1718,1719],{},"Cache",[86,1721,1722],{},"Verwendet Transistoren und Latches",[86,1724,1725],{},"Benötigt kein Auffrischen zur Vermeidung von Datenverlust",[86,1727,1728],{},"Niedrige Packungsdichte",[78,1730,1732],{"id":1731},"dram-dynamic-random-access-memory","DRAM: Dynamic Random Access Memory",[83,1734,1735,1743,1746],{},[86,1736,1737,1738],{},"Langsamer Speicher – Große Kapazität\n",[83,1739,1740],{},[86,1741,1742],{},"PC-Hauptspeicher",[86,1744,1745],{},"Verwendet Kondensatoren und wenige Transistoren",[86,1747,1748],{},"Hohe Packungsdichte",[66,1750,1752],{"id":1751},"cmos","CMOS",[11,1754,1755],{},"Verlustleistung: Im statischen Zustand fast keine Verlustleisstung -> Beim Umschalten kurzer Stromfluss durch Umladen der Transistoren",[83,1757,1758],{},[86,1759,1760],{},"Proportional zur Frequenz",[78,1762,1764],{"id":1763},"aufbau","Aufbau",[11,1766,1767],{},[14,1768],{"alt":19,"src":1769},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_2.png",[78,1771,1773],{"id":1772},"nand-aufbau","NAND-Aufbau",[11,1775,1776],{},[14,1777],{"alt":19,"src":1778},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_3.png",[78,1780,1782],{"id":1781},"nor-aufbau","NOR-Aufbau",[11,1784,1785],{},[14,1786],{"alt":19,"src":1787},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_5.png",[66,1789,1791],{"id":1790},"schaltwerke-signalspeicher","Schaltwerke (Signalspeicher)",[78,1793,1795],{"id":1794},"nichtgetaktete-flip-flops-latches","Nichtgetaktete Flip-Flops (Latches)",[101,1797,1799],{"id":1798},"rs-flip-flop","RS-Flip-Flop",[11,1801,1802],{},"Zwei Eingänge",[83,1804,1805,1808],{},[86,1806,1807],{},"Setzen",[86,1809,1810],{},"Rücksetzen",[11,1812,1813],{},"Zwei Ausgänge",[83,1815,1816,1819],{},[86,1817,1818],{},"Normal",[86,1820,1821],{},"Invertiert",[11,1823,1824],{},"Wenn ausschließlich Setzen aktiv -> Ausgang ist 1",[11,1826,1827],{},"Wenn ausschließlich Rücksetzen aktiv -> Ausgang ist 0",[11,1829,1830],{},"Wenn kein Eingang aktiv -> Letzter Zustand wird beibehalten",[11,1832,1833],{},"Wenn beide aktiv -> Verbotener Zustand (nicht definiert)",[11,1835,1836],{},[14,1837],{"alt":19,"src":1838},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_6.png",[78,1840,1842],{"id":1841},"getaktete-flip-flops","Getaktete Flip-Flops",[101,1844,1846],{"id":1845},"getaktetes-rs-flip-flop","Getaktetes RS-Flip-Flop",[11,1848,1849],{},"Wie ungetaktetes RS-Flip-Flop, bis auf:",[83,1851,1852,1855],{},[86,1853,1854],{},"Getaktetes RS-FF hat einen zusätzlichen Clock-Eingang.",[86,1856,1857],{},"Die Eingänge R & S werden erst wirksam, wenn Clock 1 ist (aufwärts Flanke)",[11,1859,1860],{},[14,1861],{"alt":19,"src":1862},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_7.png",[101,1864,1866],{"id":1865},"d-flip-flop","D-Flip-Flop",[11,1868,1869],{},"Erweiterung des getakteten RS-Flip-Flop",[83,1871,1872,1880,1883,1886],{},[86,1873,1874,1875],{},"Rücksetz-Eingang entfällt und ist stattdessen immer das Gegenteil vom Setz-Eingang\n",[83,1876,1877],{},[86,1878,1879],{},"Damit schließt man den verbotenen Zustand des RS-Flip-Flop aus.",[86,1881,1882],{},"Eingänge sind demnach nur noch D (Setzen) und ein Clock",[86,1884,1885],{},"Wenn Clock 1: Dann Ausgang = D und neg. Ausgang = neg. D",[86,1887,1888],{},"Wenn Clock 0: Vorheriger Zustand wird verwendet.",[11,1890,1891],{},[14,1892],{"alt":19,"src":1893},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_8.png",[101,1895,1897],{"id":1896},"jk-flip-flop-einflankengesteuert","JK-Flip-Flop (Einflankengesteuert)",[83,1899,1900,1903],{},[86,1901,1902],{},"Basiert auf getaktetem RS-Flip-Flop",[86,1904,1905,1906],{},"Zustände der Eingänge werden bei pos. Flange evaluiert & realisiert\n",[83,1907,1908,1911,1914],{},[86,1909,1910],{},"Verhält sich bei Zuständen, bei denen J o. K jeweils das Gegenteil sind wie RS-Flip-Flop",[86,1912,1913],{},"Sind J u. K 0 wird der vorherige Zustand beibehalten",[86,1915,1916,1917],{},"Sind J u. K 1 wird der vorherige Zustand invertiert (Toggeln)\n",[83,1918,1919],{},[86,1920,1921],{},"Schließt den verbotenen Zustand des RS-Flip-Flop aus",[11,1923,1924],{},[14,1925],{"alt":19,"src":1926},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_9.png",[101,1928,1930],{"id":1929},"t-flip-flop","T-Flip-Flop",[83,1932,1933,1936,1939,1947],{},[86,1934,1935],{},"Basiert auf JK-Flip-Flop",[86,1937,1938],{},"Kann nur Toggeln und Speichern",[86,1940,1941,1942],{},"J und K sind immer gleich\n",[83,1943,1944],{},[86,1945,1946],{},"Demnach nur ein Eingang und eine Clock",[86,1948,1949],{},"Bei 0 wird der Zustand beibehalten, bei 1 invertiert",[11,1951,1952],{},[14,1953],{"alt":19,"src":1954},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_10.png",[101,1956,1958],{"id":1957},"jk-master-slave-flip-flop-zweiflankengesteuert","JK-Master-Slave-Flip-Flop (Zweiflankengesteuert)",[83,1960,1961,1964,1975],{},[86,1962,1963],{},"Besteht aus 2 JK-Flip-Flops; Master und Slave",[86,1965,1966,1967],{},"Eingänge J u. K werden bei pos. Flanke evaluiert; bei neg. Flanke realisiert\n",[83,1968,1969,1972],{},[86,1970,1971],{},"Master: reagiert auf pos. Flanke",[86,1973,1974],{},"Slave: reagiert auf neg. Flanke (Clock negiert)",[86,1976,1977],{},"Ausgang des Masters ist Eingang des Slaves; Clock ist identisch",[11,1979,1980],{},[14,1981],{"alt":19,"src":1982},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_11.png",[11,1984,1985],{},[14,1986],{"alt":19,"src":1987},"\u002Fdownloads\u002FTIN\u002Fimages\u002F3-4-zsmf-sa2_img_12.png",[66,1989,1991],{"id":1990},"synchron-asynchronzähler","Synchron- & Asynchronzähler",[78,1993,1995],{"id":1994},"asynchronzähler","Asynchronzähler",[83,1997,1998,2006],{},[86,1999,2000,2001],{},"Gatterlaufzeit (Zeit die ein Gatter zum umschalten braucht) addiert sich\n",[83,2002,2003],{},[86,2004,2005],{},"Ausgänge sind nicht konsistent!",[86,2007,2008],{},"Einfachere Schaltung",[78,2010,2012],{"id":2011},"synchronzähler","Synchronzähler",[83,2014,2015,2023],{},[86,2016,2017,2018],{},"Alle haben den gleichen Takt\n",[83,2019,2020],{},[86,2021,2022],{},"Gatterlaufzeit immer identisch",[86,2024,2025],{},"Kompliziertere Schaltung",{"title":19,"searchDepth":20,"depth":20,"links":2027},[2028,2029,2030,2031,2032,2033,2034,2035,2036,2039,2046,2047],{"id":1621,"depth":20,"text":1622},{"id":1632,"depth":20,"text":1633},{"id":1647,"depth":20,"text":1648},{"id":1708,"depth":20,"text":1709},{"id":1731,"depth":20,"text":1732},{"id":1763,"depth":20,"text":1764},{"id":1772,"depth":20,"text":1773},{"id":1781,"depth":20,"text":1782},{"id":1794,"depth":20,"text":1795,"children":2037},[2038],{"id":1798,"depth":1545,"text":1799},{"id":1841,"depth":20,"text":1842,"children":2040},[2041,2042,2043,2044,2045],{"id":1845,"depth":1545,"text":1846},{"id":1865,"depth":1545,"text":1866},{"id":1896,"depth":1545,"text":1897},{"id":1929,"depth":1545,"text":1930},{"id":1957,"depth":1545,"text":1958},{"id":1994,"depth":20,"text":1995},{"id":2011,"depth":20,"text":2012},{},{"title":2050},"Zusammenfassung – Schulaufgabe 2 (2023\u002F2024)","\u002Ffaecher\u002Ftin\u002F3-4-zsmf-sa2","\u002Fdownloads\u002FTIN\u002FTIN_3-4_ZSMF_SA2.pdf",{"title":1601,"description":19},"faecher\u002Ftin\u002F3-4-zsmf-sa2","imxTVEz6jbJyVnfbvxDQrVZBxJOeygeK0zQdSCTw5kk",1778676319354]